Question

A flywheel of moment of inertia 2 kgm^2 is rotated at a speed of 30 rad/sec. A tangential force at the rim stops the wheel in 15 sec. Average torque of the force is
1) 4Nm. 2). 2 Nm
3) 8 Nm 4) 1 Nm

Answer 1

torque=moment of inertia*angular acceleration

angular acceleration=angular speed/time
30/15 = 2
moment of inertia=2
so,torque =4Nm

hope this answer is correct....and will help you

Answer 2

Hope this helps you.....:)