Question

A flywheel rotating at 150 rpm
slows down at a constant rate of 2
rad/s2. What is the time required to
stop the flywheel?​

Answer 1

over here I have used the 1st equation of rotational motion .. Mark me as the brainliest if you are helped..

Answer 2

Answer :

Initial frequency = 150 rpm

Final angular velocity = zero

Angular acceleration = -2 rad/s²

Here negative sign shows that angular velocity of flywheel decreases with time$.$

★ Angular acceleration is defined as the rate of change of angular velocity.

It is an axial vector quantity.

SI unit : rad/s²

First equation of rotational kinematics is given by

• ω = ω｡+ αt

ω denotes final angular velocity

ω｡ denotes initial angular velocity

α denotes angular acceleration

t denotes time

★ Conversion :

→ 1 rpm = 1/60 rps

→ 150 rpm = 150/60 = 2.5 rps

We know that, ω = 2πf

→ ω = 2π × 2.5

→ ω = 5π rad/s

By substituting the values, we get

⭆ω = ω｡+ αt

⭆ 0 = 5π + (-2)t

⭆ t = 5π/2

⭆ t = 7.85 s