Question

A flywheel used to prepare earthenware

pots is set into rotation at 100 rpm. It is

in the form of a disc of mass 10 kg and

radius 0.4 m. A lump of clay (to be taken

equivalent to a particle) of mass 1.6 kg

falls on it and adheres to it at a certain

distance x from the centre. Calculate x if

the wheel now rotates at 80 rpm.​

Answer 1

Answer:

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Dårviñ714

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Answer:

Explanation:

Moment of Inertia of flywheel = MR^2/2

I1 = 10 x 0.16 /2

I1 = 0.8 kgm2

w1 = 100 rpm

I2 = I1 + mx^2

w2 = 80 rpm

according to law of conservation of angular momentum,

I1w1 = I2w2

0.8 * 100 = (0.8 + 1.6x^2) * 80

calculating the above,

1.6x^2 = 0.2

Hence,

x = 1/2(root 2)

x = 0.35 m