Question

A flywheel used to prepare earthenware pots is set nto rotation at 100rpm. It is in the form of a disc of mass 10 kg and radius 0.4 m. A lump of clay (to be to taken equivalent to a particle ) of mass 1.6 kg falls on it and adheres to it at a certain distance x from the centre. Calculate x if the wheel now rotates at 80 rpm

Answer 1

Answer:

Explanation:

Moment of Inertia of flywheel = MR^2/2

I1 = 10 x 0.16 /2

I1 = 0.8 kgm2

w1 = 100 rpm

I2 = I1 + mx^2

w2 = 80 rpm

according to law of conservation of angular momentum,

I1w1 = I2w2

0.8 * 100 = (0.8 + 1.6x^2) * 80

calculating the above,

1.6x^2 = 0.2

Hence,

x = 1/2(root 2)

x = 0.35 m