Question

A food packet dropped from a helicopter reaches the ground in 5 s . if the velocity with which it hits the ground in 50 m/s what is the acceleration?​

Answer 1

Answer:

10m/s²

Step-by-step explanation:

t=5sec

v=50m/s

u=0

v= u + at

=> a = (v-u)/t

=(50-0)/5

=50/5=10m/s²

Answer 2

Given,

The food packet reaches the ground in 5 seconds.

Velocity while hitting the ground = 50 m/s

To find,

The acceleration of the food packet.

Solution,

We can simply solve this numerical problem by the following process.

Here,

Initial velocity (u) = 0 m/s [Starts from rest before getting dropped.]

Final velocity (v) = 50 m/s

Time (t) = 5 seconds

Acceleration (a) = ?

Now, according to kinematics formula,

v = u + at

50 = 0 + (a×5) [Putting the given values.]

0+5a = 50

a = 50/5

a = 10 m/s²

(Extra data : As, the body is falling down, here the acceleration will be gravitational acceleration.)

Hence, the acceleration will be 10 m/s²