A food packet dropped from a helicopter reaches the ground in 10 seconds. If the velocity with which it
touches the ground is 50m/s, What is its acceleration?
Answers
Answered by
4
V = 50
u=0
t=10
a= v+u/t
=50+0/10
=50/10=5m/s^2
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Answered by
1
Answer:
Acceleration = 5sec
Explanation:
t = 10 sec
u = 0 m/s
v = 50 m/s
From, v = u + at
50 = 0 + a x 10
50/10 = a
a = 5 m/s
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