Question

A food packet dropped from a helicopter reaches the ground in 10 seconds. If the velocity with which it touches ground is 50m/s, What is its acceleration? ​

Answer 1

Given :-

Time taken to reach the ground = 10 sec

Velocity with which it touches ground = 50 m/s

To Find :-

The acceleration = ?

Analysis :-

Here we are given with the time and final velocity applied.

In order to find the acceleration, substitute the values accordingly in the formula of first equation of motion.

Solution :-

We know that,

• t = Time
• v = Final velocity
• u = Initial velocity
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Final velocity (v) = 50 m/s

Initial velocity (u) = 0 m/s

Time (t) = 10 sec

Substituting their values,

⇒ 50 = 0 + (a) 10

⇒ a = v + u / t

⇒ a = 50 + 0 / 10

⇒ a = 50 / 10

⇒ a = 5 m/s

Therefore, the acceleration is 5 m/s.

Answer 2

Answer:

5 m/s²

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

• Time (t) = 10 s
• Final velocity (v) = 50 m/s
• Initial velocity (u) = 0 m/s

$\underline{\bigstar\:\textsf{To\:find:}}$

• Acceleration (a) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

We remember our 1st equation of motion i.e, $\blue{\sf{v\:=\:u\:+\:at}}$

$\implies$ 50 = 0 + a × 10

$\implies$ 50 = a × 10

$\implies\:\sf{\dfrac{50}{10}\:=\:a}$

$\implies$ 5 = a

${\large{\boxed{\sf{\therefore \: Acceleration\:is\:5\:m/s^2}}}}$

Hope it helped you dear...