Question

A food packet is dropped from a helicopter rising up with a velocity of 4 ms–1. the velocity of the packet after three seconds will be :

Answer 1

109.6 m/s will be the velocity of the food packet when trown from the helicopter

Answer 2

Answer:

The velocity of the packet after three second will be 25.4 m/s

Explanation:

Given that,

Initial velocity = 4m/s

Time = 3 sec

We need to calculate the velocity

Using equation of motion

$v = u+gt$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

Put the value in the equation

$v = 4-9.8\times3$

$v =-25.4\ m/s$

Negative sign shows the downward direction

Hence, The velocity of the packet after three second will be 25.4 m/s