Question

A food packet is dropped from a plane flying horizontally.If the time taken by the packet to reach the earth's surface is 6 seconds , calculate the height from shich the packet is dropped

Answer 1

s=ut+1/2at^2
s=1/2at^2 as u = ,0

h=1/2*9.8*6*6

h=176.4m

Answer 2

Answer:

The height from which the packet was dropped is 176.4 m.

Step-by-step explanation:

Given the problem is,

• A food packet is dropped from a plane flying horizontally.
• This means that the vertical component of the velocity of the food packet will be initially zero.
• Time taken for the packet to reach the surface of the earth is 6 seconds.  

We have to calculate the height from which the packet is dropped.

We know,

$u_y = 0\\\\a_y = 9.8\ m/s^2\\\\s_y = h = ?\\\\t = 6\ sec$

Calculating height -

$h = u_yt+\frac{1}{2} a_yt^2\\\\h = 0+\frac{1}{2} \times 9.8\times 6^2\\\\h = 176.4 \ m$

So, the height from which the packet was dropped is 176.4 m.

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