Question

A food packet is released from a helicopter which

is rising steadily at 2 ms–1. The food packet falls on

the ground after 6s. Find the height of the helicop-

ter when

(i) the food packet was released from it

(ii) when the food packet just reached the earth
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PLZ.. HELP​

Answer 1

Answer:v=-2+10*2=18m/s

Explanation:

the food packet has an initial velocity of 2 m/s in upward direction, therefore

v=-u+gt or

v=-2+10*2=18 m/s

Answer 2

v = 2+10×2 = 18 m/s

hope helps u