Question

A food packet is released from a helicopter which is rising steadily at 2 m/s after 2 sec ( i ) what is the velocity of the packet ( ii) how far is it below the helicopter?take g= 9.8m/s
2

Answer 1

Answer:

18 m/s

Explanation:

ANSWER

The food packet has an initial velocity of 2 m/s in upward direction, therefore

v=−u+gt or

v=−2+10×2=18 m/s

Answer 2

Explanation:

xkfjfivfoffigigvhdifidjfhnfbchcjgvdjdjcgdjdjfijfjdnhxhhchf