Question

A food packet is released from a plane flying horizontally, reaches the surface of the earth in 10 second. calculate the height from which the packet is dropped​

Answer 1

Answer:

The packet is dropped from the height of 176.4m

Explanation:

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Answer 2

Given: A food packet is released from a plane flying horizontally, reaches the surface of the earth in 10 seconds.

To find: The height from which the packet is dropped​.

Solution:

• In the question, the time is given as 10 seconds and the only acceleration acting on the food packet is the acceleration due to gravity (g).
• The value of acceleration due to gravity is 10ms⁻².
• Acceleration is the change in velocity with respect to time.

        $a = \frac{v}{t}$

• Here, a is the acceleration, v is the velocity of the food packet and t is the time period.

        $10ms^{-2} = \frac{v}{10s}$

        $v = 100 ms^{-1}$

• Now, velocity is the change in position of a body with respect to time.

        $v = \frac{d}{t}$

• Here, d is the distance travelled by the food packet.

        $100ms^{-1} = \frac{d}{10s}$

        $d = 1000m$

• Since the distance travelled by the food packet is 1000 m, the height from which the packet is dropped​ is 1000 m.

Therefore, the height from which the packet is dropped​ is 1000 m.