A food packet is released from a plane flying horizontally, reaches the surface of the earth in 10 second. Calculate the height from which the packet is dropped.
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Answer:
500m
Explanation:
t=10s
u=0m/s
g=10m/s^2
y=h
-h=Usintheta -1/2gt^2
y= 1/2 gt^2
y= 1/2×10×100
y= 500m
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