A food packet was dropped from an aircraft flying horizontally 6 second before it hits the ground it was at a height of 780 M and had travelled a distance of 1 km horizontally find the speed and altitude of the aeroplane
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Answer: 360km/hr,1.28km
Explanation:
780=usinθ×6+12×g×36
780−180=usinθ×6
using θ=6006=100m/sec
i.e. food package dropped before 10 secs
1000=u×10⇒u=100m/s
∴H=g×(16)22=1280m.
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