A foodpacket dropped from a helicopter reaches the ground is 5s.If the velocity with which it hits the ground is 50m/s.what is the acceleration
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Explanation:
since here it's not given the velocity of the helicopter, consider it to be static at the sky
therefor
initial velocity of the food packet =u=0m/s
final velocity =50m/s
acceleration =a =?
time taken by the foodpacket to reach the ground =t =5s
according to formula
v=u+at
50=0+(a×5)
a=10m/s²
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