A foot ball match may be either won, drawn or lost by the host country's team. So there are three ways of forecasting the result of any one match. One correct and two incorrect. Find the probability of forecasting at least three correct result for four matches.
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0
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I calculated it as 19 but I am not satisfied with my answer as someone I know calculated it different and his answer is 581 . So please assist in finding the answer and approach.
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2
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Given, There are three ways of forecasting the result of any one football match, one correct and other two incorrect.
so,probability of incorrect result =2/3
therefore, probability of forecasting at least 3 correct result for 4 matches = probability of 3 correct and 1 correct or probability of all 4 correct
= 4*(1/3)^3 * (2/3) + (1/3)^4
=(1/3)^4 (8+1)
=9/3^4
=1/9 , mark me brainliest
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