a foot of a ladder is 6m away from a wall and its top reaches a window 8m above the ground.if the ladder is shifted in such a way that its feet is 8m away from the wall,to what height does its top reaches
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Step by step explanation :-
Given: AC=8 m and BC=6 m
Using the Pythagoras theorem, we get
(AB)
2
=(AC)
2
+(BC)
2
⇒(AB)
2
=(8)
2
+(6)
2
⇒(AB)
2
=64+36
⇒(AB)
2
=100
⇒(AB)=
1
00
⇒AB=10
∴ Length of the ladder =10 m
When the ladder is shifted:
Let the height of the ladder after it is shifted be H m.
By using the Pythagoras theorem, we can find the height of the ladder after it is shifted.
8
2
+H
2
=10
2
⇒H
2
=10
2
−8
2
⇒H
2
=100−64
⇒H
2
=36
⇒H=
3
6
⇒H=6
Thus, the height of the ladder is 6 m.
I hope it helped u...
Anonymous:
hi
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