Question

a foot of an elephant has an area of 275 m2 if the force exerted by by by the elephant is 22×10 cube N then what would be the pressure exerted​

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JEE-MAIN

Physics

Grade 11

Fluid dynamics

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The foot of an elephant has an area of 275 cm2. If the mass of the elephant is 2200 kg, find the pressure exerted by the elephant on the ground ( g = 10ms−2). If your answers x finds the value of x105.

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Hint Pressure is defined by us as the force which is perpendicular to the surface of an object per unit area over which the force that is exerted is distributed. With the help of this concept we can solve this question.

Complete step by step answer

We know that the area of one foot = 275 cm2.

Now we can write that:

275×10−4m2(∴1cm2=10−4m2)

But the total force is acting through the four legs. So, total area of the four feet (A), which is equal to: 4×275×10−4m2

The mass of the elephant (m) = 2200 kg

The value of g is given as 10 ms−2.

The force exerted by the elephant is equal to the weight of the elephant.

P=mgA(∴F=W−mg)

Substituting the values in the above equation, we get:

P=2200×104×275×10−4=22×103×1041100

=22×10711×102

P = 2×105Pa

Therefore, the pressure exerted by the elephant is 2×105Pa