A foot path of uniform width runs all around outside of a rectangular field 30 M long and 24 why did the part occupies an area of 360 metre square find its width
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Answer:
- The width of the path = 3 m
Given :
- The length of the rectangular field = 30 m.
- The width of the rectangular field = 24 m.
- The Area of the rectangular field = 360 m².
To find :
- The width of the path =?
Step-by-step explanation:
Let the width of the path be x.
Then, the length of the rectangular field and path =2x+30
So, breadth =2x+24
And, Area of rectangular field =(30×24)
=720
Therefore, Area of the rectangular field and path =(2x+30)(2x+24)
Now,
According to the question :
(2x+30) (2x+24)−720 = 360
⇒4x 2 +48x+60x+720−720=360
⇒4x 2 +108x−360=0
⇒x 2 +27x−90=0
⇒x 2 +30x−3x−90=0
⇒x(x+30)−3(x+30)=0
⇒(x+30)(x−3)=0
⇒x=−30 and x=3
Negative value is not valid,
So, We have to take positive value = 3.
Thus, the width of the path = 3 m
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