a football is shoot from a distance of 50 m how far it will go and which angle
Answers
Answered by
3
Answer:
Angle of projection θ=30
0
initial velocity, μ=15 m/sec
a) Maximum height =
2g
μ
2
sin
2
θ
=
2×9.8
(15)
2
×sin
2
30
0
=2.869 m
b) Time of flight for projectile =
g
2μsinθ
=
9.8
2×15×sin30
0
=1.53 sec
c) Range =
g
μ
2
sin2θ
=
9.8
(15)
2
×sin60
0
=
9.8
225
×
2
3
=19.74 m
Answered by
1
Answer:
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