A football kicked with a speed of 19.2 ms' has a range which is 4 times the
maximum height reached by it. Find its range.
plz answer fast
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Answer: 37.616
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Answer:
height ={(v^2)(sin^2theta)}/2g
where theta is 90°
as max height is needed
max height =v^2/2g=(19.2×19.2)/9.8×2
Range = 4 × max height = (4×19.2×19.2)/(9.8×2)=75.23m
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