Question

A football leaves the foot of a punter at an angle of 54° positive x-
direction) at a speed of 21 m/s. Determine the horizontal and vertical
components of the velocity.
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Answer 1

Answer:

horizontal component = 12.6 m/s.

vertical component = 16.8 m/s.

Explaination:

Given that, projectile velocity of the ball ,u= 21m/s

and projectile angle = x = $54^{0}$.

The horizontal component of velocity = $u_{x }= ucosx$

                                                                       $= 21*\frac{4}{5}$ = 16.8m/s.

The vertical component of velocity = $u_{y}=usinx$

                                                                   $= 21*\frac{3}{5}$ =12.6m/s.