Question

A football of mass 0.5 kg coming towards player with a velocity of 10 m/s. Player hit straight back the football with velocity 15 m/s. If the contact time is 0.02 second then the average force involved is: - (1) 250 N (2) 1250 N (3) 500 N (4) 625 N

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Answer 1

Answer:

The average force involved is (4) 625 N.

Explanation:

We have,

Mass (m) = 0.5 Kg

Initial velocity (u) = 10 m/s

Final velocity (v) = 15 m/s

Contact time (t) = 0.02 sec

To find,

Average force (F)

Solution,

Using the formula,

=> Force = Chane in momentum/Time taken

Change in momentum:

>> P = mv

=> P = 0.5 × (-15 - 10)

=> P = 0.5 × 25

∴ Momentum = -12.5 Kg.m/s

Now,

=> Force = -12.5/0.02

∴ Force = 625 N

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Answer 2

Answer:

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