Physics, asked by ayush0017, 10 months ago

A football of mass 0.5 kg is kicked by a player with the velocity of 5m/s before reaching to another player of his Team he returns it by kicking, along its original path with the velocity 6m/s. Calculate the magnitude of change in linear momentum of the football ⚽ due to second kick.

I WILL MARK U AS A BRAINLIEST
BUT ANSWER WIL FULL PROCESS

AND NO SPAM!!!!!! ​

Answers

Answered by tabish92
5

Answer:

0.5 kg m/s

Explanation:

p(momentum)= mass * velocity

& ∆ momentum= mass*∆velocty

∆means change .

p1= 0.5*5m/s

=2.5 kg m/s

p2= 0.5*6m/s

= 3.0 kg m/s.

therefore ∆momentum=p2-p1

= (3.0-2.5)kg m/s

= 0.5 kg m/s

Answered by Anonymous
2

Answer:

p=mv

p=mvpf-pi=Delta p

p=mvpf-pi=Delta ppfinal = -5/10*6

p=mvpf-pi=Delta ppfinal = -5/10*6pinitial =5/10*5

p=mvpf-pi=Delta ppfinal = -5/10*6pinitial =5/10*5-3-2.5= -5.5= change in momentum -represent direction.

Similar questions