A football of mass 0.5 kg is kicked by a player with the velocity of 5m/s before reaching to another player of his Team he returns it by kicking, along its original path with the velocity 6m/s. Calculate the magnitude of change in linear momentum of the football ⚽ due to second kick.
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Answers
Answered by
5
Answer:
0.5 kg m/s
Explanation:
p(momentum)= mass * velocity
& ∆ momentum= mass*∆velocty
∆means change .
p1= 0.5*5m/s
=2.5 kg m/s
p2= 0.5*6m/s
= 3.0 kg m/s.
therefore ∆momentum=p2-p1
= (3.0-2.5)kg m/s
= 0.5 kg m/s
Answered by
2
Answer:
p=mv
p=mvpf-pi=Delta p
p=mvpf-pi=Delta ppfinal = -5/10*6
p=mvpf-pi=Delta ppfinal = -5/10*6pinitial =5/10*5
p=mvpf-pi=Delta ppfinal = -5/10*6pinitial =5/10*5-3-2.5= -5.5= change in momentum -represent direction.
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