Question

A football player initially at rest accelerates uniformly as she runs down the field, travelling 17 m [E] in 3.8 s. What is her final velocity?

Answer 1

Using the equation: $x=u\times t + \frac{1}{2}\times a\times t^{2}$
where x=17m, u=0 and t=3.8s, we get a=2.36m/s^2.
From the equation: $v=u+ at$
where u=0 m/s, a=2.36 m/s^2 and t=3.8s, we get v=8.97 m/s