Physics, asked by alismanggalisp8v52b, 1 year ago

A football player initially at rest accelerates uniformly as she runs down the field, travelling 17 m [E] in 3.8 s. What is her final velocity?

Answers

Answered by har3nd3rpapssj

Using the equation: $x=u\times t + \frac{1}{2}\times a\times t^{2}$
where x=17m, u=0 and t=3.8s, we get a=2.36m/s^2.
From the equation: $v=u+ at$
where u=0 m/s, a=2.36 m/s^2 and t=3.8s, we get v=8.97 m/s

alismanggalisp8v52b: Thanks friend, but what is 'u'? i don't get that

safwanasairasaj: u is initial velocity and as it say the body is initially at rest so it will be o

alismanggalisp8v52b: Thanks a lot for helping :)

alismanggalisp8v52b: acceleration how you get 2.36m/s2?

har3nd3rpapssj: As u=0m/s, then x=0.5*a*t^2. Therefore, a=2*x/t^2=(2x17)/3.8^2=2.36m/s^2

alismanggalisp8v52b: Thank you

har3nd3rpapssj: Your Welcome!

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