a football player is tackled by another player and lands with their combined weight of both player on his knee if the combined weight of players is 2400 Newton and the players knee measures 0.1 metre by 0.1 metre how much pressure is exerted on the turg when a player lands on his knee
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Here's your answer...
When the two players fall, the force exerted by the players on the turf will be equal to the force exerted by the turf on the players, by Newton's third law.
So F = 2400 N
The area of contact between the turf and the knees will also be the same as the measures of the knees. However, there are two knees, so the total area will be doubled.
So A = 2×0.1×0.1 m²
P = F/A
= 2400/2×0.1×0.1
= 1200×100
= 120000 Pa
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Here's your answer...
When the two players fall, the force exerted by the players on the turf will be equal to the force exerted by the turf on the players, by Newton's third law.
So F = 2400 N
The area of contact between the turf and the knees will also be the same as the measures of the knees. However, there are two knees, so the total area will be doubled.
So A = 2×0.1×0.1 m²
P = F/A
= 2400/2×0.1×0.1
= 1200×100
= 120000 Pa
[0110100101]... More questions detected... [010110011110]
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//This is your friendly neighbourhood UnknownDude
thegreat1234:
solve my 2nd question plzz
in my profile
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Answer:
= 240 000
Explanation:
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