Question

a football player kicks a ball at an angle of 37 degree to the horizontal with an initial speed of 15 metre per second assuming that the ball travelled in a vertical plane calculate the time at which the ball reaches the highest point and the maximum height reached and the horizontal range of the projectile and the time for which the ball is in air​

Answer 1

Answer:

at max. height velocity will be 0

so using. v=u-gt

0=15-10t. g=10m/s2

t=1.5sec

Explanation:

h max= u2sin2theta/2g

225×sin37xsin37/2x10

225x3/5×3/5÷20

=4.05m

horizontal range = ux ×time of flights

u2×2 (sin theta.cos theta)÷g

225×2 (sin37.cos37)/10

450 (3/5×4/5)/10

=21.6m.

the ball is in air= time of flight

=2usin theta/g

2×15×sin37/10

30×3÷5/10

=1.8sec

Answer 2

Answer:

   ans is :     1.8

see

time of  flight =2u.sin theta\g

so,

30*0.6\10

=1.8

note* sin 37=3/5

Explanation: