Question

a football player throws a ball with a velocity of 50 metre per second at an angle of 30° from the horizontal the ball remains in air for how much time

Answer 1

here is your answer.... please check it...

Answer 2

Answer:

You need to consider the vertical component of velocity

Now vertical:

The initial vertical velocity = 50 sin(30) = 25 ms^-1

Velocity = 0 ms^-1 in this direction.

Acceleration = -9.81 ms^-2

Time = x

We can find time by using v = u + at

Rearrange for t = (v-u)/a

0 - 25 / -9.81 = 2.548 seconds.

But hang on, we have only found the time taken to reach the peak height, so to find how long it is in the air in total, we need to double the value of time.

2.548 x 2 = 5.096 seconds ≈ 5.1 seconds in air