Question

A football punter accelerates a 0.59 kg football from rest to a speed of 6.6 m/s in 0.34 s, what constant force does the punter exert on the ball?

Answer 1

Answer:

11.4 N

Explanation:

Given:

$u = 0 \: m {s}^{ - 1} \\ v = 6.6 \: m {s}^{ - 1} \\ t = 0.34 \: s \\ m = 0.59 \: kg$

$v = u + at \\ a = \frac{v - u}{t} \\ = \frac{6.6}{0.34} = 19.4 \: m {s}^{ - 2}$

$f = ma \\ = 0.59 \times 19.4 \\ = 11.4 \: newton$