Question

A football team won 40 games from total they played this was 80% of the total. How many games were played in all
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Answer 1

Answer :

›»› The number of total game were played in all is 50.

Given :

• A football team won 40 games from total they played this was 80% of the total.

To Find :

• How many games were played in all?

Solution :

Let us assume that, the number of total game played is "x".

According to the given question,

→ Total they played of x = Football team won.

→ 80% of x = 40

We can write this,

→ 80/100 * x = 40

Cancel 0 from 80 and cancel 0 from 100,

→ 8/10 * x = 40

Divide 8 by 10,

→ 4/5 * x = 40

Organize the multiplication,

→ 4x/5 = 40

Multiply both sides by the least common multiple for the denominators to eliminate the fraction,

→ 4x = 5 * 40

Multiply 5 and 40,

→ 4x = 200

Divide both sides by the same number,

→ x = 200 ÷ 4

Divide 200 by 4,

→ x = 50

Hence, the number of total game were played in all is 50.

Verification :

→ 80% of x = 40

→ 80/100 * 50 = 40

→ 8/10 * 50 = 40

→ 8/1 * 5 = 40

→ 8 * 5 = 40

→ 40 = 40

Here, LHS = RHS.

Hence Verified !

Answer 2

Answer:

$\huge \bf \: required \: answer$

Total games won by Football team = 40

Total percentage of game they won = 80%

Assume that the number of gàmes to be x

Now,

$\sf \: 80\% \: of \: x \: = 40$

We will find the value of x

$\sf \dfrac{80}{100} \: of \: x = 40$

$\sf \: \dfrac{8}{10} \times x = 40$

$\sf \dfrac {4}{5} \times x = 40$

$\sf \dfrac {4x}{5} \: = 40$

$\sf \: 4x = 5 \times 40$

$\sf \: 4x = 200$

$\sf \: x = \frac{200}{40}$

$\sf \: x = 50$

Let's verify it

$\sf \: 80\% \: \times 50 = 40$

$\frac{80}{100} \times 50 = 40$

$\sf \frac{8}{10} \times 50 = 40$

$\sf \: 8 \times 5 = 40$

$\sf \: 40 = 40$

LHS = RHS

Hence verified