Question

A football team won 40% of the total number of matches it played during a year. If it lost 6 matches in
all and no match was drawn, find the total number of matches played by the team during the year.
(1) 20
(2) 8
(3) 12
(4) 10
​

Answer 1

Answer:

10 matches

Step-by-step explanation:

won 40% matches and therefore lost 60% matches

now lost matches = 6 matches that is 60% matches

60%+x%= 100 %

x = 40%

therefore 60/100 + 40/100 = 10 matches

Answer 2

The total number of matches played by the team during the year was 10.

(4) is the correct option.

Step-by-step explanation:

Let the team played x matches during the year.

Now, it has been given that, team won 40% of the total matches.

So, number of matches the team won that years = 0.4x

And given that number of matches lost = 6.

Therefore, we have the equation

0.4 x + 6 = x

Subtract 0.4x to both sides

6 = x - 0.4 x

6 = 0.6 x

Divide both sides by 0.6

x = 10

Therefore, the total number of matches played by the team during the year was 10.

(4) is the correct option.

#Learn More:

A football team won 70% of the matches it played in a year. find total number of matches played in the year, if the team lost 15 matches and no match ended in a draw.

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