Question

A football thrown over a level field travels a horizontal distance of 17 m before hitting the o ground. The point of release is 1.5 m above the ground and the projection angle is 16 . What is the ball’s initial speed?

Answer 1

Answer:

Angle of projection θ=300

initial velocity, μ=15 m/sec

a) Maximum height =2gμ2sin2θ

                                 =2×9.8(15)2×sin2300

                                 =2.869 m

b) Time of flight for projectile =g2μsinθ

                                                 =9.82×15×sin300

                                                 =1.53 sec

c) Range =gμ2sin2θ

                =9.8(15)2×sin600=9.8225×23

                =19.74 m

Explanation:

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