Question

A footballer kicks a ball on horizontal ground giving it an initial of 20 m/s at an angle of 45 degree to the horizontal.Where will the ball land?

Please give me the answer in full detailed in paper​

Answer 1

This will help u bro

Answer 2

The ball will land 2m away from the point the ball is kicked.....

firstly.... Hi there....

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this question is related to projectile motion, and u need to bear in mind, that the motion can be visualized purely in terms of 2D... so components of velocity can be resolved....

vector form of general equation of a projectile,

s = ut + 1/2 at²

where the letters in bold are vector quantities....

$\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}u cosz\\u sinz\end{array}\right]t+1/2\left[\begin{array}{ccc}0\\-g\end{array}\right]t^{2}$

This will b easier for u to understand.... the first row of the matrix represents x drxn, and second row represents y direction in a 2D system.

t= time

z=the angle made by the velocity vector with the x axis

u=initial velocity

x and y are the respective distances from the origin.

R=Range

$\left[\begin{array}{ccc}R\\0\end{array}\right]=\left[\begin{array}{ccc}u cosz\\u sinz\end{array}\right]t+1/2\left[\begin{array}{ccc}0\\-g\end{array}\right]t^{2}$

taking individual coordinates we get t=2u sinz/g

and R= u cosz t

R = u² sin2z/g

substituting t and values as, u = 20 z=45 and g=10

we get R =40m

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Cheers..