Question

a footballer kicks a ball on horizontal ground giving it an initial velocity of 20 m/s at an angle of 45 degree to the horizontal where will the ball land​

Answer 1

Answer:

The answer will be 40 m

Explanation:

According to the problem the velocity of the ball is 20 m/s =V

The ball is thrown with an angle of 45 degree with the horizontal,

Now the distance at which the ball will land , say l

l = v^2 sin2theta/g

Now putting the values,

l = (20)^2 sin2x 45 /10

  = 400 sin90/10 = 40 m

Answer 2

Answer:

This tests the time of flight of a horizontal projection.

Time of flight = 2 U sin 45° / g

U = 20 m/s

g = 10

Sin 45 = 0.7071

(2 × 20 × 0.7071) / 10 = 2.8284 Seconds

Explanation: