Question

A footballer kicks a ball on horizontal ground giving it an initial
velocity of 25 m/s at an angle of 30° to the horizontal.


a). Where will the ball be 1.2 seconds after it is kicked?


b). What will be the greatest height reached by the ball?


c). Where will the ball land? (horizontal distance)

​

Answer 1

Answer:

Angle of projection θ=30

0

initial velocity, μ=15 m/sec

a) Maximum height =

2g

μ

2

sin

2

θ

=

2×9.8

(15)

2

×sin

2

30

0

=2.869 m

b) Time of flight for projectile =

g

2μsinθ

=

9.8

2×15×sin30

0

=1.53 sec

c) Range =

g

μ

2

sin2θ

=

9.8

(15)

2

×sin60

0

=

9.8

225

×

2

3

=19.74 m