Question

A foothpath of uniform width runs around inside of a rectangular field 38m long and 32m wide. if the path occupied 600m2 find the width.

Answer 1

Answer:

Step-by-step explanation:

given:

length of outer rectangle=38 m

breadth of outer rectangle=32 m

path occupied =600 sq m

now,

let width =x

length of inner rectangle=38-2 x

breadth of inner rectangle=32-2 x

therefore,

area of outer rectangle-area of inner rectangle=path occupied

38* 32 [(38-2 x)(32-2 x)]=600

1216-[38(32-2 x)-2 x(32-2 x)]=600

1216-[1216-76 x-64 x+4 x 2]=600

1216-[1216- 4872 x +4 x 2]=600

1216-1216+4872 x-4 x 2=600

0=4 x 2- 4872 x+600

I have given u the little idea how to solve rest plz u try

hope it helps u!!

thank u!!