A footpath of uniform width runs all around The inside of a rectangular field is 50m long and38m wide. If the area of the path is 492m2 find its width
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Let X = path width. Then
(2*50*X) + (2*((38 - 2X) * X)) = 492
100X + 76X -4X^2 = 492
4X^2 -176X + 492 = 0
X^2 - 44X + 123= 0
Using an online quadratic equation solver, the value of X (the path width) is 3 meters wide.
EDIT
I corrected the last part of my equation. I forgot to double the width, as I did the first part,The final answer is 3 meters
(2*50*X) + (2*((38 - 2X) * X)) = 492
100X + 76X -4X^2 = 492
4X^2 -176X + 492 = 0
X^2 - 44X + 123= 0
Using an online quadratic equation solver, the value of X (the path width) is 3 meters wide.
EDIT
I corrected the last part of my equation. I forgot to double the width, as I did the first part,The final answer is 3 meters
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