Question

a. For the circuit shown in the given picture, Calculate
i) equivalent resistance ii) Current

Answer 1

Answer:

From the circuit, Resistors of resistance 5 and 10 are connected in parallel.

So their effective resistance is given by

1/R eq=1/R1+1/R2

R eq=R1 R2/R1+R2

So R eq = 5×10/5+10= 3.33

This R eq is connected with 7 in series,

So total effective resistance is 7+3.33= 10.33

Current = V/Total effective resistance

Current=6/10.33=0.58 A

Answer 2

Answer:

Equivalent resistance of parallel connection of 5 and 10 = (5×10)/(5+10)= 50/15 = 10/3

Equivalent resistance of the circuit = 7 + 10/3 = 31/3 ohm

Voltage in the circuit = 6 V

Current flowing through the circuit = Voltage/Equivalent resistance

Current flowing through the circuit = 6 / (31/3) = 18/31 amperes

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Explanation: