Question

a) For the gp 1/27,1/9,1/3, , ,,.....81 ; Find the product of fourth term from the beginning and the
fourth term from the end. →
please.... ​
it's urgent

Answer 1

Answer:

3

Step-by-step explanation:

Given GP = (1/27), (1/9), (1/3).... 81

Here,

Common ratio = (1/9) * (27/1) = 3.

First term, a = (1/27)

Last term, l = 81

4th term from beginning

= ar³

= (1/27) * 3³

= 1

4th term from the end

= l/r³

= l/3³

= 81/27

= 3

Now,

Product of fourth term from beginning and end :

= 1 * 3

= 3

Hope it helps!

Answer 2

Answer:

a1=1/27

an=81

r=3

an=a1*r^(n-1)

r^(n-1)=an/a1 = 81*27 = 2187

r= (2187)^(1/(n-1))

3=2187^(1/(n-1))

n-1 = 7

n = 8

we need the product of a4*a(n-4)= a4*a4 = 1