Question

A force 1.0N acts on body of mass 10 kg. As a result the body covers 100 cm in 4 seconds moving along
a straight line. It's initial velocity is

a) 0.5 cms -
b) 5 cms - 1
c) 50 cms - 1
d)1/5cms-1​

Answer 1

Explanation:

A force of 11 N acts on a body of mass 1010 kg. Consequently, the body covers a distance of 100100 cm in 44 seconds. We want to determine the initial velocity of the body.

a=Fm,a=Fm, where a,Fa,F and mm are the acceleration, force and mass respectively.

⇒a=110⇒a=110 m/s 2.2.

s=ut+12at2,s=ut+12at2, where s,us,u and tt are the distance covered, initial velocity and time, respectively.

⇒0.1=u×4+12×110×(4)2=4u+45.⇒0.1=u×4+12×110×(4)2=4u+45.

⇒4u=0.1−45=−710.⇒4u=0.1−45=−710.

⇒u=−740⇒u=−740 m/s.

⇒⇒ The initial velocity is 740740 m/s in the direction opposite to that of the force.

Answer 2

Answer:

1/20m/sec which is 5cm/s

Explanation:

F= mass×accelaration

so from the formula s=ut+at²

we get the initial velocity