Question

A force 100 N acts on a body. If the units of mass and
length are doubled and unit of time is halved, then
the force in the new system changes to
(A) 160 N
(8) 1.6 N
(C) 16 N
(D) 1600 N​

Answer 1

Answer:1600

Explanation:

F=ma

Also F=mv/t

But v=l/t

So,F is proportional to ml/t^2

Than check on the image to get full answer.

Answer 2

The new dimension of force is 1600 N and option(D) is correct.  

Explanation:

Given:

A force 100 N acts on a body.

The units of mass and length are doubled and unit of time is halved.

To Find:

The force in the new system changes.

Solution:

As given,A force 100 N acts on a body.

Let magnitude of force = 100N

Mass=M, Length=L and Time =T

Dimension of force F $=[MLT^{-2}]$

                       $[MLT^{-2}]=100$

For the new system change.

As given,the units of mass and length are doubled and unit of time is halved.

ass $M'=2 M$

Length $L'=2 L$

Time $T'=\frac{1}{2} T$

The new dimension of force  $=[M'L'T'^{-2}]$.

                    $[M'L'T'^{-2} ]=[2M. 2L.( \frac{T}{2} )^{-2} ]$

                                       $=16[MLT^{-2} ]$

  The new dimension of force F $=16\times100$

                                                                $=1600 N$

Thus, the new dimension of force is 1600 N and option(D) is correct.      

      #SPJ2