Question

A force 100 N acts on a body of mass 2kg for 10sec. the change in the velocity of the body​

Answer 1

Answer:

Given : F=100 N m=2 kg t=10 s

Change in momentum of the body m(Δv)=F.t

where Δv is the change in velocity.

⟹ 2×Δv=100×10

⟹ Δv=500 m/s

Answer 2

Answer:

force= 100N

mass= 2kg

$f = ma$

$100 = 2 \times a$

$a = \frac{100}{2}$

$a = 50ms ^{ - 2}$

a=50 m/s² t= 10s

$a = \frac{Δv}{Δt}$

$50 = \frac{Δv} {10}$

$Δv = 50 \times 10$

$Δv = 500ms ^{ - 1}$

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