Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculater work (cas 60=1/2)​

Answer 1

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Given:-

$\longrightarrow$ Force = 10 N

$\longrightarrow$ mass = 10 kg

$\longrightarrow$ Angle = 60⁰

$\longrightarrow$ displacement = 5 m

$\longrightarrow$ Cos60⁰ = $\sf\dfrac{1}{2}$

To find:-

$\longrightarrow$ Work done

Formula to be used:-

$\longrightarrow$ $\underline{\boxed{\sf work\: done = Force × displacement × CosØ}}$

Solution:-

$\implies$ $\sf Work\:done = 10 × 5 × \dfrac{1}{2}$

$\implies$$\sf work\: done = 5 × 5$

$\implies$$\sf work\: done = 25 Joules$

$\small\bf\pink{@itzsplendidcharm࿐}$

Answer 2

Answer:

AnSwer࿐

Given:-

\longrightarrow⟶ Force = 10 N

\longrightarrow⟶ mass = 10 kg

\longrightarrow⟶ Angle = 60⁰

\longrightarrow⟶ displacement = 5 m

\longrightarrow⟶ Cos60⁰ = \sf\dfrac{1}{2}

2

1

To find:-

\longrightarrow⟶ Work done

Formula to be used:-

\longrightarrow⟶ \underline{\boxed{\sf work\: done = Force × displacement × CosØ}}

workdone=Force×displacement×CosØ

Solution:-

\implies⟹ \sf Work\:done = 10 × 5 × \dfrac{1}{2}Workdone=10×5×

2

1

\implies⟹ \sf work\: done = 5 × 5 workdone=5×5

\implies⟹ \sf work\: done = 25 Joulesworkdone=25Joules