Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

Answer 1

Given

• Force = 10N
• Displacement = 5m
• Angle between the force and the displacement is 60°

To Find

• Work Done

Solution

☯ Work = Fs cosθ

• Here as the value of θ is 60°, then the value of cosθ = cos 60° whose value is ½

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✭ According to the Question :

→ Work = Fs cosθ

• F = Force = 10 N
• s = Displacement = 5 m
• θ = Angle between the force & the Displacement = 60°

→ Work = 10 × 5 × cos 60°

→ Work = 10 × 5 × ½

→ Work = 50 × ½

→ Work = 25 J

∴ The work done by the force is 25 J

Answer 2

Answer:

Given :-

• A force 10 N acts on a block af mass 10 kg at an angle of 60° displaces it 5 metre. (cos 60° = ½)

To Find :-

• What is the work.

Formula Used :-

${\red{\boxed{\large{\bold{Work\: Done\: =\: Fs\: Cos\theta}}}}}$

where,

• F = Force
• s = Displacement
• $\theta$ = Angle between applied force and displacement.

Solution :-

Given :

• Force = 10 N
• Displacement = 5 m

According to the question by using the formula we get,

⇒ $\sf Work\: Done =\: Fs\: Cos\theta$

( As we know that, Cos$\theta =\: \dfrac{1}{2}$ )

⇒ $\sf Work\: Done =\: {\cancel{10}} \times 5 \times \dfrac{1}{\cancel{2}}$

⇒ $\sf Work\: Done =\: 5 \times 5$

➠ $\sf\bold{\purple{Work\: Done =\: 25\: J}}$

$\therefore$ The work done is 25 J .