Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

Answer 1

Given:-

• a force 10N.
• displaces it 5M.
• angle between the force and the displacement is 60°

To Find :-

• Work done

Solution

☯work = FC cosø

⇛work = 10 × 15 × 5 × cos 60°

⇛work = 10 × 15 × ½

⇛work = 25 J

Answer 2

Answer:

Correct QUESTION :-

A force of 10N acts on a block of mass 10kg at an angle of 60° displaces it 5m. calculate the work done. (cos 60°=1/2).

Given:-

Force Applied = 10N

Mass of Block = 10kg

Angle made = 60° = 1/2

Displacement ( s ) = 5m

To Find:-

Work Done.

Formulae used:-

Work Done = F × s × Cos O

Now,

→ Work Done = F × s × cos 60°

→ Work done = 10 × 5 × 1/2

→ Work done= 25J

Hence, The work done by the force is 25J.