Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

Answer 1

Step-by-step explanation:

คɴᎦᴡєя

☆ɢɪᴠᴇɴ :-

☛juA force 10 N acts on a block af mass 10 kg at an angle of 60° displaces it 5 metre. (cos 60° = ½)

☆ ᴛᴏ ғɪɴᴅ :-

☛What is the work.

☆ғᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

WorkDone=FsCosθ

where,

☘F = Force

☘s = Displacement

☘θ = Angle between applied force and displacement.ғɪsʜ

sᴏʟᴜᴛɪᴏɴ :-

ɢɪᴠᴇɴ:

Force = 10 N

Displacement = 5 m

According to the question by using the formula we get,

$[tex]\sf Work\: Done =\: Fs\: Cos\thetaWorkDone=FsCosθ$[/tex]

$As We know that</p><p></p><p>\theta =\: \dfrac{1}{2}θ=21</p><p></p><p>\sf Work\: Done =\: {\cancel{10}} \times 5 \times \dfrac{1}{\cancel{2}}WorkDone=10×5×21</p><p></p><p>\sf Work\: Done =\: 5 \times5WorkDone=5×5</p><p></p><p>\therefore\sf\mathfrak{\pink{Work\: Done =\: 25\: J}}∴WorkDone=25J</p><p></p><p>$