Question

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

Answer 1

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Work done in fruit case =F.S.cosθ

=10×2×cos60

=10J

Work done in second case is same as 10J=FScosθ

⇒F×2×cos30=10

F= 10/√3N

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Answer 2

Answer:

☯︎ᴡᴏʀᴋ ᴅᴏɴᴇ= 25 ᴊ

sᴇᴇ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ ᴘɪᴄ

Step-by-step explanation:

sᴏʀʀʏ ғᴏʀ ʟᴀᴛᴇ ᴀɴsᴡᴇʀ