Question

A force 1200 newton acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface.

Answer 1

P=1200÷0.0010
= 12000000÷10
=1200000Pa

Answer 2

as we know preesure= force/area. so preesure=1200/10=120 PA. and as we know 1 thrust=4.45 Newton. so 1200 Newton=1200*4.45=5340n. hope it helps you