a force 200N pulls a sledge of mass 50kg andovercomes a constant frictional forceof 40 .calculate the acceleration of the sledge
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Answer:
3.2 m/s^2
Explanation:
The force 200N is opposed by frictional force of 40N
Therefore net force acting on the sledge is:
Fn=200-40=160N
F=ma
substitute the given obtained data in the formula
160=50×a
a=160/50
a=3.2 m/s^2
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