Question

A force 2i^ + 4j^ acts in xy plane. Angle made by this force with +x axis will be_
answer is tan-¹ (2)
please explain the steps

WRONG ANSWERS WILL BE REPORTED​

Answer 1

A given force is acting, in x-y plane:

$\small \rm \vec{F} = 2\hat{i} + 4\hat{j}$

$\sf \tan \theta = \frac{perpendicular}{base}$

$\small \: \sf \: tan \theta = \frac{dy}{dx}$

$tan \theta = \frac{4}{2} = 2$

$\theta = {tan}^{ - 1} (2)$